AQA GCSE Chemistry Reactivity of Metals

C5.2

Displacement Reactions

When a more reactive metal takes the place of a less reactive one

What is a Displacement Reaction?

A displacement reaction occurs when a more reactive metal takes the place of a less reactive metal in a compound (usually a metal salt solution).

A more reactive metal can displace a less reactive metal from a solution of its salt. This happens because the more reactive metal more readily loses electrons and forms ions.

more reactive metal + less reactive metal salt → less reactive metal + more reactive metal salt

Example: If you put iron into copper sulfate solution:

iron + copper sulfate → iron sulfate + copper

Iron is more reactive than copper, so it displaces copper from the solution.

A displacement reaction only occurs if the metal added is more reactive than the metal in the compound. If it's less reactive, there is no reaction.

Predicting Displacement Reactions

Use the reactivity series to predict whether a displacement reaction will occur:

Metal Added Solution Reaction? Reason
Zinc Copper sulfate Yes Zn is more reactive than Cu
Iron Copper sulfate Yes Fe is more reactive than Cu
Copper Iron sulfate No Cu is less reactive than Fe
Magnesium Zinc chloride Yes Mg is more reactive than Zn
Copper Silver nitrate Yes Cu is more reactive than Ag
Silver Copper sulfate No Ag is less reactive than Cu

Observations in Displacement Reactions

When a displacement reaction occurs, you can typically observe:

Reaction What You See
Iron + copper sulfate solution Blue solution turns pale green; orange/brown coating of copper forms on the iron
Zinc + copper sulfate solution Blue solution turns colourless; reddish-brown copper appears on the zinc
Magnesium + copper sulfate solution Blue solution turns colourless; brown/pink copper coats the magnesium; solution gets hot
Copper + silver nitrate solution Colourless solution turns blue; silvery crystals of silver form on the copper
Remember: the solution changes colour because the metal ions in solution change. Copper sulfate is blue because of Cu2+ ions. When copper is displaced, the blue colour disappears.

Balanced Symbol Equations with State Symbols

Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)
Zn(s) + CuSO4(aq) → ZnSO4(aq) + Cu(s)
Mg(s) + ZnCl2(aq) → MgCl2(aq) + Zn(s)
Cu(s) + 2AgNO3(aq) → Cu(NO3)2(aq) + 2Ag(s)

State symbols:

Ionic Equations H

In a displacement reaction, the spectator ions (ions that don't change) can be removed to give the ionic equation. This shows only the particles that actually react.

Full equation:

Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)

Written with ions:

Fe(s) + Cu2+(aq) + SO42−(aq) → Fe2+(aq) + SO42−(aq) + Cu(s)

The sulfate ions (SO42−) appear on both sides – they are spectator ions. Remove them:

Ionic equation:

Fe(s) + Cu2+(aq) → Fe2+(aq) + Cu(s)

Oxidation & Reduction: Electron Transfer H

Oxidation is the loss of electrons.
Reduction is the gain of electrons.
Remember: OIL RIG – Oxidation Is Loss, Reduction Is Gain.

In the displacement reaction between iron and copper sulfate:

Fe(s) + Cu2+(aq) → Fe2+(aq) + Cu(s)

Half equations:

Fe → Fe2+ + 2e−   (oxidation)
Cu2+ + 2e− → Cu   (reduction)

The more reactive metal is always the one that is oxidised (it loses electrons more readily). The less reactive metal ion is reduced (it gains electrons and becomes a metal atom).

In an exam, identify which species is oxidised and reduced by looking at the charges. If something goes from 0 charge to a positive charge, it has lost electrons (oxidised). If something goes from a positive charge to 0, it has gained electrons (reduced).

Practice Questions

Question 1 1 mark

Which of the following pairs will produce a displacement reaction?

Correct!

Zinc is more reactive than iron, so zinc can displace iron from iron sulfate solution. In all other options, the metal added is less reactive than the metal in the solution.

Question 2 3 marks

A student places a piece of magnesium into copper sulfate solution. Describe what they would observe and explain why this reaction occurs.

Model Answer

The blue copper sulfate solution would turn colourless [1 mark]. A brown/orange coating of copper would appear on the magnesium [1 mark]. This happens because magnesium is more reactive than copper, so it displaces the copper from the solution [1 mark].

Question 3 1 mark

In the reaction Fe + CuSO4 → FeSO4 + Cu, which species is reduced?

Correct!

Copper ions (Cu2+) gain electrons to become copper atoms (Cu). Gaining electrons is reduction. Iron is oxidised (it loses electrons to form Fe2+).

Question 4 2 marks

Write a balanced symbol equation, with state symbols, for the displacement reaction between zinc and copper sulfate solution.

Model Answer
Zn(s) + CuSO4(aq) → ZnSO4(aq) + Cu(s)

[1 mark for correct formulae and balancing, 1 mark for state symbols]

Question 5 H 4 marks

For the reaction between magnesium and copper sulfate solution:

  1. Write the ionic equation. [1 mark]
  2. Write the half equation for oxidation. [1 mark]
  3. Write the half equation for reduction. [1 mark]
  4. Explain which species is the reducing agent. [1 mark]
Model Answer

(a)

Mg(s) + Cu2+(aq) → Mg2+(aq) + Cu(s)

(b) Oxidation half equation:

Mg → Mg2+ + 2e−

(c) Reduction half equation:

Cu2+ + 2e− → Cu

(d) Magnesium is the reducing agent because it donates/loses electrons to the copper ions, causing the copper ions to be reduced.

Question 6 1 mark

A student adds copper to silver nitrate solution. What colour change would they observe in the solution?

Correct!

Silver nitrate solution is colourless. As copper displaces the silver, copper ions (Cu2+) go into solution, turning it blue. Silver crystals form on the copper.

Question 7 2 marks

Explain why adding copper to magnesium sulfate solution does not produce a reaction.

Model Answer

Copper is less reactive than magnesium [1 mark]. A less reactive metal cannot displace a more reactive metal from a solution of its salt [1 mark].